QUESTION 1
1. Find the vertices and locate the foci for the hyperbola whose equation is given.
81y2 – 64×2 = 5184
vertices: (-8, 0), (8, 0)
foci: (- , 0), ( , 0)
vertices: (0, -8), (0, 8)
foci: (0, – ), (0, )
vertices: (0, -9), (0, 9)
foci: (0, – ), (0, )
vertices: (-9, 0), (9, 0)
foci: (- , 0), ( , 0)
4 points
QUESTION 2
1. Find the vertices and locate the foci for the hyperbola whose equation is given.
49×2 – 16y2 = 784
vertices: (-4, 0), (4, 0)
foci: (- , 0), ( , 0)
vertices: (0, -4), (0, 4)
foci: (0, – ), (0, )
vertices: (-4, 0), (4, 0)
foci: (- , 0), ( , 0)
vertices: (-7, 0), (7, 0)
foci: (- , 0), ( , 0)
4 points
QUESTION 3
1. Find the standard form of the equation of the hyperbola satisfying the given conditions.
Center: (6, 5); Focus: (3, 5); Vertex: (5, 5)
– (y – 6)2 = 1
– (y – 5)2 = 1
(x – 5)2 – = 1
(x – 6)2 – = 1
4 points
QUESTION 4
1. Solve the problem.
An experimental model for a suspension bridge is built. In one section, cable runs from the top of one tower down to the roadway, just touching it there, and up again to the top of a second tower. The towers are both 6.25 inches tall and stand 50 inches apart. At some point along the road from the lowest point of the cable, the cable is 1 inches above the roadway. Find the distance between that point and the base of the nearest tower.
10.2 in.
15 in.
9.8 in.
15.2 in.
4 points
QUESTION 5
1. Solve the problem.
An experimental model for a suspension bridge is built. In one section, cable runs from the top of one tower down to the roadway, just touching it there, and up again to the top of a second tower. The towers stand 40 inches apart. At a point between the towers and 10 inches along the road from the base of one tower, the cable is 1 inches above the roadway. Find the height of the towers.
4 in.
4.5 in.
6 in.
3.5 in.
4 points
QUESTION 6
1. Find the standard form of the equation of the ellipse satisfying the given conditions.
Major axis vertical with length 16; length of minor axis = 6; center (0, 0)
+ = 1
+ = 1
+ = 1
+ = 1
4 points
QUESTION 7
1. Identify the equation as a parabola, circle, ellipse, or hyperbola.
12y = 3(x + 8)2
Circle
Hyperbola
Parabola
Ellipse
4 points
QUESTION 8
1. Find the vertices and locate the foci for the hyperbola whose equation is given.
y = ±
vertices: (0, -2 ), (0, 2 )
foci: (0, -2 ), (0, 2 )
vertices: (-2 , 0), (2 , 0)
foci: (-2 , 0), (2 , 0)
vertices: (-12, 0), (12, 0)
foci: (-2 , 0), (2 , 0)
vertices: (-12, 0), (12, 0)
foci: (-2 , 0), (2 , 0)
4 points
QUESTION 9
1. Find the standard form of the equation of the ellipse satisfying the given conditions.
Foci: (0, -2), (0, 2); y-intercepts: -3 and 3
+ = 1
+ = 1
+ = 1
+ = 1
4 points
QUESTION 10
1. Find the standard form of the equation of the parabola using the information given.
Vertex: (4, -7); Focus: (3, -7)
(y + 7)2 = -4(x – 4)
(x + 4)2 = -16(y – 7)
(x + 4)2 = 16(y – 7)
(y + 7)2 = 4(x – 4)
4 points
QUESTION 11
1. Find the standard form of the equation of the hyperbola satisfying the given conditions.
Endpoints of transverse axis: (0, -10), (0, 10); asymptote: y = x
– = 1
– = 1
– = 1
– = 1
4 points
QUESTION 12
1. Convert the equation to the standard form for a hyperbola by completing the square on x and y.
4y2 – 25×2 – 16y + 100x – 184 = 0
– = 1
– = 1
– = 1
– = 1
4 points
QUESTION 13
1. Find the standard form of the equation of the ellipse satisfying the given conditions.
Major axis horizontal with length 12; length of minor axis = 6; center (0, 0)
+ = 1
+ = 1
+ = 1
+ = 1
4 points
QUESTION 14
1. Find the standard form of the equation of the parabola using the information given.
Focus: (3, 3); Directrix: y = -5
(x – 3)2 = 16(y + 1)
(y + 1)2 = 16(x – 3)
(y – 3)2 = 16(x + 1)
(x + 1)2 = 16(y – 3)
4 points
QUESTION 15
1. Convert the equation to the standard form for a parabola by completing the square on x or y as appropriate.
x2 – 6x – 6y – 21 = 0
(x + 3)2 = 6(y + 5)
(x – 3)2 = 6(y – 5)
(x – 3)2 = 6(y + 5)
(x + 3)2 = -6(y + 5)
4 points
QUESTION 16
1. Convert the equation to the standard form for a hyperbola by completing the square on x and y.
4×2 – 25y2 – 8x + 50y – 121 = 0
– = 1
– = 1
– = 1
– = 1
4 points
QUESTION 17
1. Find the standard form of the equation of the parabola using the information given.
Focus: (-3, -1); Directrix: x = 7
(x – 2)2 = -20(y + 1)
(y + 1)2 = -20(x – 2)
(y – 2)2 = -20(x + 1)
(x + 1)2 = -20(y – 2)
4 points
QUESTION 18
1. Convert the equation to the standard form for a parabola by completing the square on x or y as appropriate.
y2 – 4y – 2x – 2 = 0
(y – 2)2 = 2(x + 3)
(y + 2)2 = -2(x + 3)
(y + 2)2 = 2(x + 3)
(y – 2)2 = 2(x – 3)
4 points
QUESTION 19
1. Identify the equation as a parabola, circle, ellipse, or hyperbola.
4×2 = 36 – 4y2
Parabola
Hyperbola
Ellipse
Circle
4 points
QUESTION 20
1. Find the standard form of the equation of the ellipse satisfying the given conditions.
Endpoints of major axis: (10, -3) and (-2, -3); endpoints of minor axis: (4, -1) and (4, -5)
+ = 1
+ = 1
+ = 0
+ = 1
4 points
QUESTION 21
1. Identify the equation as a parabola, circle, ellipse, or hyperbola.
2x = 2y2 – 30
Ellipse
Circle
Parabola
Hyperbola
4 points
QUESTION 22
1. Find the standard form of the equation of the hyperbola satisfying the given conditions.
Endpoints of transverse axis: (-6, 0), (6, 0); foci: (-7, 0), (-7, 0)
– = 1
– = 1
– = 1
– = 1
4 points
QUESTION 23
1. Find the standard form of the equation of the ellipse satisfying the given conditions.
Endpoints of major axis: and ; endpoints of minor axis: and
+ = 1
+ = 1
+ = 1
+ = 1
4 points
QUESTION 24
1. Identify the equation as a parabola, circle, ellipse, or hyperbola.
(x – 2)2 = 16 – y2
Circle
Ellipse
Hyperbola
Parabola
4 points
QUESTION 25
1. Identify the equation as a parabola, circle, ellipse, or hyperbola.
9×2 = 4y2 + 36
Hyperbola
Ellipse
Parabola
Circle
Looking for the best essay writer? Click below to have a customized paper written as per your requirements.
